5x^2+25=128

Solution for 5x^2+25=128 equation:

5x^2+25=128

We move all terms to the left:

5x^2+25-(128)=0

We add all the numbers together, and all the variables

5x^2-103=0

a = 5; b = 0; c = -103;
Δ = b2-4ac
Δ = 02-4·5·(-103)
Δ = 2060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2060}=\sqrt{4*515}=\sqrt{4}*\sqrt{515}=2\sqrt{515}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{515}}{2*5}=\frac{0-2\sqrt{515}}{10}
=-\frac{2\sqrt{515}}{10}
=-\frac{\sqrt{515}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{515}}{2*5}=\frac{0+2\sqrt{515}}{10}
=\frac{2\sqrt{515}}{10}
=\frac{\sqrt{515}}{5}
$